Question Description
Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared
according to
the JEE exam syllabus. Information about Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam.
Find important definitions, questions, meanings, examples, exercises and tests below for Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer?.
Solutions for Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Let Pbe the relation defined on the set of all real numbers such that P={(a,b):sec2a−tan2b=1}.. Then, Pisa)reflexive and symmetric but not transitiveb)symmetric and transitive but not reflexivec)reflexive and transitive but not symmetricd)an equivalence relationCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.